1the fig pposted by atgs leads to the right ans which is 3.95......devika ur ans is wrong... uttara ..sorry cant see ur ans
find the resistance between the points a and b.
please show me the full solution
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19 Answers
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49
so this boils down to
now we hav 2 find resis b/w A n B nothing else...
1oh come on... lets put a smile on that face......from wat angle r u seeing that u r getting one more ans.!
1This is kinda really easy. First we make circuit diagram. Dont ask me why I have split the middle part; it is how we do calculations in our skool. Actually i dont knw the actual reason why it is done.
For the upper triangle, net resistance = 12/7 ohm
Hence for the upper branch the net resistance = 4 + 12/7 + 6 = 82/7 ohm---------(1)
For the bottom triangle, net resistance = 56/11 ohm----------(2)
Now use parallel combination of resistors formula, and u find the net resistance of (1) and (2).
Hence net resistance of the entire network = 3.54 ohms.
49yeh exactly.......and thus no current flows through r resistance system and so the resistance may be neglected
23bhargava , der is no potential difference across r , hence it is short
1i think dat 6,8,14 are in parallel giving R.and 4,2,12 are in parallel giving r.now r and R are in series.
1yup...subhomoy is correct.....jus short the wire along teh diagonal.....then basically it will be teh eq resis of 6,14 and 8 connected in parallel....
49the above according to me is absolutely wrong....
answer is coming 168/61Ω