the main concept here is the density of electron pair on nitrogen atom ! me and et groups ,due to their strong electron donating abilities repel the l.p on nitrogen atom ! what we need to know is that the repulsion due to 1 ethyl group is more than that due to 1methyl group(in fact 2 methyl groups)...hence ,
3>2>1>4
...also, going by the experimentally found pka value , the pka for methyl aniline is 4.85 and that for the ethyl aniline is 5.11 (more the pka , the more is the basicity)

Explain the order for the methyl aniline and ethyl aniline..
The rest are obvious
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UP 0 DOWN 0 0 5

5 Answers
Pritish Chakraborty
·2009-11-30 07:06:18
2 > 3 > 1 > 4?
2 would be greatest, followed by 3 for presence of alkyl group, and then 1 which has just nitrogen's lone pair, and the aldehyde group sucks electrons from the ring.
Asish Mahapatra
·2009-11-30 07:08:08
2>3 why??
isnt ethyl group more elecrton releasing than methyl ??
Pritish Chakraborty
·2009-11-30 07:10:40
This is more of basics of organic from 11th..so I'm not so well versed in those lol. Wait for other replies.
Debotosh..
·2009-11-30 07:21:51