simple, draw the resonance structures...
see where the positive charge CAN appear. ull get 1357 only
predict the site of reactivity for the above reaction
a) 1,2,3,4,5,6,7
b)1,3,5,7
c)2,4,6
d)1,4,7
ans
please explain.....
i think its d,as oh is a nucleophile and therefore electron rich,it wud search the site wich easily accepts electron,nd 1,4,7 might b the right site,if not then may b its due to +i effect
ans is b
can u plz elaborate ur explanation with a suitable diagram...
why is it not 2,4,6
simple, draw the resonance structures...
see where the positive charge CAN appear. ull get 1357 only
will not the hydride shift occur from the carbon containing Cl to give an 3° carbcation with more stability and resonce stabilized by Cl