1581.Ph-CHBr-CH2CH3
2.Ph-CBr=CH2
3.??in the propene branch,the ring is bonded to 1st or 2nd carbon???
Dwijaraj Paul Chowdhury obviously 1st carbonUpvote·0· Reply ·2013-08-05 06:35:37
11 Answers
481Rate of reaction-3>1>2
See the reaction will proceed with the formation of carbocation.......So SN1.....ab SN1 mein 3°>2°>1°...I hope this is d answer.....
158
9963) 1-chloro,1-propenyl ,cyclo hexane
- Anurag Ghosh An idiotic question but is Ph a source of electrons???....getting confused??
- Anurag Ghosh And Swarna wat did u do in d third one???.....give me d mechanism.....
13Swarna ur answer is wrong....try again..
- Swarna Kamal Dhyawala then what is the answer
996
Jeet Sen Sharma this cannot be correct atleast i think so.....
Prashant Kulthia this is the correct ans accrding to me because the carbocation formed is very stable...
1maybe ans wud be 
- Divyans Jhunjhunwala can this be the reason...
as before reaction the ring having a π(pi) bond follows (4n+2)π rule so its aromatic but if we remove the bond we are disturbing the aromaticity so i think this wud be the correct answer.
481Hmmmm...Divyansh lagta hai tu r8 hai......didn't observed d pi bond inside...:P We r disturbing d aromaticity of d compound......
- Divyans Jhunjhunwala The decision Rests with harsh about the correct answer... :-)
- Swarna Kamal Dhyawala @anurag from were can u see it is aromatic
13i just cant believe dat none of got it right......hehehe...cant stop laughing!!!!
- Swarna Kamal Dhyawala in this case we r getting 2 degree carbocation but in 1-2 addition we get three degree carbocation
- Jeet Sen Sharma are u sure....?? this is the ans..?? y ??
1357It is not aromatic all are not sp2 hybridized
Answer given by swarna seems correct to me