that is not naoch that is naoch3
i'm sorry
12 Answers
the structure of NaOCH is
and in the reactant, this will happen
so NaOCH will get attached to the rings through O and HI and HCl will be eliminated.
this is what i think will happen. i hope it is correct.
I think NaCl will be out, with the methoxide ion attaching itself in place of Cl.
soumik , here elimination will be much more favourable than substitution ,since methoxide ion is a strong enough base for elimination , and even heat is provided , and hence ultimately , elimination should occur
NaOCH3 will be
it can be written as
in reactant same mechanism will take place.
Cl and I will get attached to CH2Na. and oH will get attached to the rings.
the Cl and 1 H will get out of the substrate forming
and methane and NaCl will be the side products