The smallest ketone and its next homologue are reacted with NH2OH to forn oxime.
(a) two different oximes are formed.
(b)three diff oximes are formed .
(c)two oximes are optically active.
(d) all oximes are optically active.

plzzz give the reason along with the answer.

6 Answers

Pritish Chakraborty ·

The smallest ketone is, I think, acetone? And it's next homologue is CH3-CO-CH2-CH3.
I think it's pretty obvious that two different oximes are formed. About optical activity I'm not so sure.

mohit sengar ·

ans is (b)

golu pro ·

ans is b) becauz 1 form from acetone while next homologue is butan-2-one or butane-3-one
there4 3 oxime r formed!!!!!

mohit sengar ·

butan-2-one and butan-3-one are not two different compound .

qwerty ·

there will b 3

when acetone is reacted we get 1 oxime

when next homologue is reacted we get an oxime , which can either be E form or Z form
( i.e like cis /trans ) bcz of the bulky lone pair on N .

Amor Iqbal ·

As @mohit senger said in his answer, acetone forms one oxime and butanone forms two oximes, one E and the other, Z. They are not optically active despite what is written in arihant's 39 years jee chemistry question bank.

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