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In a reaction : A + 2B \Leftrightarrow 2C,2 moles of A,3 moles of B and 2 moles of C are placed in 2 L flask and the eqb concentration of C is 0.5 mole/L.The eqb constant (K) for the reaction is
(a). 0.073
(b). 0.147
(c). 0.05
(d). 0.026

4 Answers

29
govind ·

Ans...C..

11
Gone.. ·

yes..thats what is given

29
govind ·

So wat ans r u getting?

i did it like this

A + 2B = 2C
conc(moles/l) at t = 0 1 1.5 1
and at equilibrium 1.25 2 0.5

now apply the formula K = [C]2 / [A] [B]2

u will get the answer as C..

11
Gone.. ·

o damn..i did'nt take into acc the vol of flask..i was taking it 1L and doing..thanks govind.

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