1nishant sir please u only check.
match list 1(complex) with list 2(no. of unpaired electrons) and select correct answer.
list 1 list 2
A [CrF6]4- 1
B [MnF6]4- 2
C [Cr(CN)6]4- 3
D [Mn(CN)6]4- 4
A B C D
(a) 4 1 2 5
(b) 2 5 3 1
(c) 4 5 3 1
(d) 2 1 3 5
i think answer (c) is correct.
am i correct.
i asking if i am correct or not as answer to this question is not given in book.
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9 Answers
1no of unpaired electrons toh nikal lo bus e- configuration se....
Cr+2 ->no pairing as F is weak ligand. [3d4]
Mn+2 -> no pairing again. [3d5]
Cr+2 -> pairing, as CN- is a strong ligand. [3d5 but pairing is there.]
Mn+2 -> pairing agian... [3d5 but pairing ... ]
1oh,sir i think u r not replying coz u gave a pink to skygirl and think her reply to be absolutely correct.....huh
but plz read her reply properly for third compound(C) she says pairing wud take place but if pairing had taken place then there wud only be one unpaired electron but in answer there is no option.
so i think it wud be better if u urself look into it.
1357In A charge is +2 EC is d4
as ligand is weak it will be t2g3eg1
no. of unpaired electrons=4
In B charge is +2 EC is d5
as ligand is weak it will be t2g3eg2
no. of unpaired electrons=5
In C charge is +2 EC is d4
as ligand is strong it will be t2g4eg0
no. of unpaired electrons=2
In A charge is +2 EC is d5
as ligand is weak it will be t2g5eg0
no. of unpaired electrons=1
