# cha;llenge to bakshi and qwerty

For dissociation of PCl5 if relative molar mass is M and total pressure at equilibrium is p at a density d and temperature d,find an expression for degree of dissociation.If vapor density has a value 62 when temperature is 230Â°C what is value of p/d!

1
kunl ·

If you succeed to solve the one above then u would take this one with a little more care

At temp. T: 2AB2(g) =2AB(g)+B2(g)
with a degree of dissociation x.Find expression of x in terms of Kp and total pressure p!

1
kunl ·

final blow:
30 cm long tube is partition by thin weakly conducting frictionless separator.Ideal gases filled in two parts.In beginning temperature of two parts A and B is 400K and 100K.Separator slides to a momentary rest when length of A is 20cm.Find final final equilibrium position!

71
Vivek @ Born this Way ·

By the way, Nice collection!

49
Subhomoy Bakshi ·

3) the eqm (i think) will be 10cm for side A!

And ye kya hai bhai?
why 2 of us??

49
Subhomoy Bakshi ·

2) i am getting,

KP=4x3P(1+x)(1-2x)2

approximating x<<1

we get,

x=\left( {\frac{K_P}{4P}}\right)^{\frac{1}{3}}

tell me if i am wrong! [1]

1
kunl ·

bigada kuch nai....koi attempt karta nahin hai mere doubts seedhe se toh thought of a twist[3][3]

bhai u r right for 1st one plz post full solution for third one[1]....i mean 3rd one[1]

1
kunl ·

second ka answer is little wrong[1]

49
Subhomoy Bakshi ·

3)

in initial case, pressure must be equated at both ends!

thus,

p(2V)=n1R(4T)
p(V)=n2R(T)

gives n1:n2=1:2

n1=k
n2=2k

at second case,
the p and T on both sides will be same!

using the data we get A=10 cm side!

1
kunl ·

(2K/p)1/3

49
Subhomoy Bakshi ·

ohh shit!! :P

i took 2x in place of ur x! :D :D :D

1
kunl ·

anyone for 1st question??

1
swordfish ·

Is the answer for first part of first question
PM/dRT - 1 ?