**·**2013-04-24 17:53:35

Dada first see whether my approach is correct or not......

-d[A]/dt=k[A] (As the reaction is first order w.r.t A and B is present in excess)

Given,the initial concentration of A is 0.1M.Let the final concentration be xM.

A.T.P

âˆ«d[A]/[A]=-âˆ«k.dt (Integration limit for [A] is from 0.1 to x and integration limit for time is from 0 to 100 secs)

After integrating we get,

log[x]-log(0.1)=-5*10^-1

[x]=10^-3/2........whether this is correct????

- Anurag Ghosh sry I forgot to write the unit of [x] i.e. 10^-3/2M...

·0·Reply·2013-04-22 23:04:34