2 g of P4 reacts completely with 2 g of o2 to produce P4O6 and P4O10... find the weight of P4O6 and P4O10 produced.?
106P4 + 3O2 --> P4O6
x/(96) x/32 (moles)
P4 + 5O2 ----> P4O10
(2-x)/160 (2-x)/32
Let wt of O2 reacted to form P4O6 be x
then wt of O2 reacted to form P4O10 = (2-x)
given that [x/96 + (2-x)/160]*31*4 = 2
x can be solved (x=0.87 g)
and hence wt of P4O6 and P4O10 can also be calculated
11ashish..thanx for replying ... but i did'nt quite understand your method...for the frst rxn... what is x/96.... moreover even if i consider 0.87 gm of O2 reacted to form P4O6....the weight of P4O6 formed with 0.87 gms of O2.. does'nt gove the ans....
Just for ur concinience the ans is 1.999gms of P4O6 is formed and 2.001 gms of P4O10 is formed.... this ques is from RC Mukherjee.. Chapter 2 .
29@Asish in that first equation hows that X/96 and in the second (2-x)/160?...btw molecular mass of phosphorus is 31..so it shud be x/124 and (2-x) / 124
11@Asish i think u forgot to multiply the stochiometry co-efficient
106perhaps made a mistake..
was writing the solution without pen and paper... will verify after boards.. pls bear with it until then...
others are welcome to post correct solutions
1357Let the wt. of P4O6=x M=
and that of P4O10=y
then we have x+y=4 (conservation of mass)
mole of P4O6=x/220
Wt. of P=4*31*x/220
Wt. of P is P4O10=4*31*y/284
Total wt. of P=2 g
find x and y