ELECTRO CHEM....

A constant current flowed for 2 hours through a potassium iodide solution oxidizing the iodide ion to iodine

2I- -> I2 + 2e-

At the end of the experiment, the iodine was titrated with 21.75 ml of 0.0831 M sodium thiosulphate solution

I2 + 2S2O32- -> 2I- + S4O62-

WHAT WAS THE AVERAGE RATE OF CURRENT FLOW IN AMPERES??

ANS :- 0.0242 A

4 Answers

1
prateek punj ·

hey guys also look into this one...

62
Lokesh Verma ·

21.75 x 0.0831 x 2 milli moles of electron!

21.75 x 0.0831 x 6.023 x 1023 x 10-3 x2 electrons

21.75 x 0.0831 x 2 x 6.023 x 1023-3 x 1.6 x 10-19 x2 couloumb of charge...

in 2 hours = 7200 seconds

current will be ... 0.0242x2 A

am I making some mistake??

1
prateek punj ·

mera ans bhi yehi aa raha tha paar aapne first line main 2 multiply kiske liye kiya hai iodine or thiosulphate....

1
prateek punj ·

yaar isko try karo....

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