equivalent weight

hey guys could anyone explain how to find equvalent weight in reaction such as,

example 1-

4KMnO4 + 5HC2O4.H2C2O4.2H2O + 13H2SO4 → 4MnSO4 + 9KHSO4 +20CO2 + 18H2O

the equivalent weight of potassium tetraoxalate crystals are?
a-84.76
b-63.5
c-127
d-158.75

answer given is option b

example 2-

find the equivalent weight of K2Cr2O7 (molecular weight=M)

reaction

K2Cr2O7 + HCl → KCl + CrCl3 + Cl2 + H2O

my question is why do we need to balance the reactions only in some reactions to find the equivalent weight .

Regards,
gp

4 Answers

71
Vivek @ Born this Way ·

In case of redox reactions,to calculate the equivalent weight of a particular compound, you need to calculate the n-factor. But for that you'll have the write up the oxidation and reduction reaction which in turn are used for balancing the reaction.

71
Vivek @ Born this Way ·

In Non redox reaction, the Equivalent weight is simply like E = M/No of H atoms lost (for acids) and so on.

1
funkygp ·

could you give the method of finding the nfactor after balancing the rxn.
(i can't recall the method of doing it)

thanks,
gp

71
Vivek @ Born this Way ·

please search for it on google or on go iit.

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