1haan wahi galtise likh diya
calculate enthalphy of combustion of propane in KJ /mol at 298K
given
BE (o=o)=410 kj/mol
BE(c=o)=804
BE(c-h)=410
BE(o-h)=464
BE(c-c)=345
resonance enrgy of CO@ is -143kj/mol
del H(vap) (h20 ,l)=41kj /mol
wat i did was
BE (products)-BE(reacnts )
so
BE products =(8C-h)+(2c-c)+5(o=o)
BEreacnts =(3(c=o)+8(o-h)+resonce enrgy
tellme wethr m rite or wrng
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4 Answers
11yahan pe
wat i did was
BE (products)-BE(reacnts )
so
BE products =(8C-h)+(2c-c)+5(o=o)
BEreacnts =(3(c=o)+8(o-h)+resonce enrgy
ΔH= B.E (reactants )-B.E(products ) hota hai