Midnight Numerical on Ionic Equilibria

Calculate the pH of the solution by mixing 50 ml of N-HCl and 30 ml of N-NaOH solution assuming both to be completely dissociated in normal solution.

1 Answers

1357

Manish Shankar ·2008-10-31 11:38:53

millimoles of HCl=millieq. of HCl=NV=50*1=50
millimoles of NaOH=millieq. of NaOH=30*1=30

millimoles of HCl neutralized by NaOH=30
millimoles of HCl left=50-30=20

total volume of mixture=50+30=80 ml

[HCl]=millimol/V=20/80=0.25 M

pH=-log[H⁺]=-log0.25=1-log2.5=1-0.4=0.6

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