1molality = 150/98= 1.53
What is the molality of 15% solution of H2SO4 by mass??
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10 Answers
615% bole toh in 100gm mein tera 85 gm h2so4 hai......
1let solution = 100 g
hence H2SO4 = 15g
so solvent = 85g = 0.085 kg
molality = (15/98) / 0.085
Now calculate yourself
6oh ...i made a mistake..yeah here in 100gm soln 15gm is h2s04...wat i did was for 85 %...dats y i was getting wrong ans....same on me....
1Moles of H2SO4 = 15/98
Mass of water = 75/18
thus molality = 15/98 X 18/75
Is this a wrong method??
13Yeh kya hai bhai -
" Mass of water = 75/18 " ?!
Its given ki 100gm sol.n => 85 gm water =o.085kg water.
m=moles/kg of solvent, same wht aveek did.
115% by mass means 15g of solute present in 100g solution.
So, mass of solvent=100-15=85g
Now by formula Molality=15 X 100098 X 85 m
Which = 1.8007 m
(ans.)