ek example do naa... then i can explain.
how to find the n factor for the salts which react such that no atom undergoes change in oxidation state
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if no atom undergoes change in oxidation state then it is a simple double displacement reaction .. simply balance the atoms on either side ..
reaction of Na3PO4 with BaCl2 to form Ba3(PO4)2
can we find n factor without balancing , i mean through gain or loss of electrons
here n-factor is simply the cationic charge or anionic charge isn't it ? for example Na3PO4 .. n-factor = 3 ??
ok asish but can u solve through gain or loss of electrons
yes ashish is right.
but n-factor is generally FOR A PARTICULAR REACTION.
it changes for the same compound from reaction to reaction.
8X10,
u can calculate gain or loss with reaspest to the reaction it is undergoing.
nothing to mind! but wat whole solution ?
u din ask any question!
for na3po4 as asish said it is 3.
but if like
na3po4 + h20 ---> Na2HPO4 + NaOH
here n-factor of NA3PO4 is 1 as there is only 1 replacement H.
theek hai sky, main samajh gaya. lekin ek aur concept hota hai in which v can find n factor through gain or loss of electrons. mera is method se answer nai aa rha ya main concept theek nai lga pa ra. if u know this concept then please explain through this method