nice one

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#Chemistry #Physical Chemistry

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8 Answers

1

Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-04-04 09:32:23

isse bhi dekh lo bhai

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13

Ð”Ð²Ò¥Ñ—ÑuÏ now in medical c ·2009-04-04 09:34:26

second one 6.1....

[(14-11.6)+9.8]/2

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Ð”Ð²Ò¥Ñ—ÑuÏ now in medical c ·2009-04-04 09:41:16

is the first one D

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Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-04-04 09:43:07

i dunno d answers
post ur method

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Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-04-04 10:17:24

koi toh bata bhi do ..sharmao mat

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Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-04-05 08:52:47

abhirup plez gimme d sol

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Ð”Ð²Ò¥Ñ—ÑuÏ now in medical c ·2009-04-05 08:58:44

i ve done the 2nd one...#4

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1357

Manish Shankar ·2009-04-07 19:57:27

for I
(+ -)+H₂Oâ†’(-)+H₃O⁺

Ka given is 1.6*10^-10

K_b=K_w/K_a=10^-14/1.6*10^-10=6.25*10^-5

For second

As it exist as zwitter ion in solution

pH=[pKa(NH₃⁺---)+pK_a(-COOH)]/2=[9.8+14-11.6]/2=6.1

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Your Answer

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