1try this too!
in an oswald walker experiment,dry air was first blown thru a solution containing solute(M=278) in 150 g of water and then also thru pure water.the loss in mass of water is 0.0827g while mass of water absorbed in sulphuric acid is 3.317g.calculate the amount of slute.
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1357Po is proportional to mass of water absorbed by sulfuric acid=3.317g
Po-P is proportional to loss in mass of water=0.0827 g
(Po-P)/Po=Xsolute
now find the mass of the solute
1why
Po is proportional to mass of water absorbed by sulfuric acid=3.317g
Po-P is proportional to loss in mass of water=0.0827 g
1sir,is it a rule that we have to take it as u have mentioned in post in an oswald-walker experiment.
like as u have given-
[Po is proportional to mass of water absorbed by sulfuric acid=3.317g
Po-P is proportional to loss in mass of water=0.0827 g]
is it so we have to take it similar always in an oswald-walker experiment.
39www.textbooksonline.tn.nic.in/Books/11/Chemistry-EM/Vol2/c11.pdf
thats the link man
1357(Po-P)/P0=XB
(Po-P)/P=nB/nA=WBMA/WAMB
WB=[(Po-P)/P]*WAMB/MA
W=[0.0827/(3.317-0.0827)]*150*278/18=59.24 gm