Proof

For reaction,
A_(g)â†”B_(g)+C_(g)
prove that K_p=Î±²(K_p+P)

5 Answers

What are you saying ?
:-(

you have to simply prove that

K_p=Î±²P/(1-Î±²)

which to me seems not correct!

oh sorry ! i din't got it to be (ABâ†’A+B) FORM. sorry again !!!!!!!!!!!!!!!!!!!

A(g) â†’ B(g) + C(g)
1-a a a
total moles = 1+a , p_A=1-a/1+a , p_B=a/1+a , p_C=a/1+a

K_p = [a²/(1+a)²] / [1-a/1+a]
now, solve it to get K_p=a²(K_p+P)

sir , the only assumption is that the initial concentration is 1 M.

I am getting
K_p=Î±²(1+K_p)
:-(

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