481I could have done it in this way....
Molecular Mass of the element=density*volume = 24 x 10-24*7.20
Now, no. of atoms= no. of moles*(6.02*10^23)
no. of moles(n)=200/M.W
Now you can proceed..
The cubic type of cell may be required to calculate the effective no. of atoms in the cubic unit cell i.e
8/8 + 12/2 =7
Rajiv Agarwal The calculation of the effective number of atoms in the cubic cell needs to be looked at. Its given "having one atom in each corner of the cube and two atoms on one of its face diagonals" - so 8/8 + 2*(1/2) = 2
Only one of the face diagonals. Anurag's calculations would be right if it were all the face diagonals.Upvote·0· Reply ·2014-03-27 21:26:54- Anurag Ghosh Ohh yess sir,i didn't see that it was one of the face diagonals.....
Sahil Jain but the in solution the effective no. of atoms is given 3 in p bhadhur ....9 in comprehensive and 2 in dinesh publication- Anurag Ghosh 2 is the ri8 answer......