1well 1 mole of caco3 reacts with 2 moles of hcl. find no: of mles of caco3 in 50 gm. 2 x that will be no: of moles of hcl./ then use 20% realtion to get the weight of sample
a sample of hydrochloric acid contains 20% of hydrocloride by mass .how many grams of this acid sample is necessary to completely interact with 50 g of calcium carbonate?
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3 Answers
1
1357moles of CaCO3=1/2
moles of HCl required=2*1/2=1
weight of HCl required=36.5 g
100 gm of sample has HCl =20 gm
20 gm of HCl is in 100 gm sample
36.5 gm of HCl is in (100/20)36.5=5*36.5=182.5 gm