RCM (28)
A heat pump is used to draw water from a well.The temperature of the water is 15°C and that of the atmosphere is 40°C.If the amount of water drawn is 10kg through a depth of 12m, calculate the amount of heat supplied to the well.
24Work done=change in potetial enegy of water=10*10*12=1200 J
now coeff of performance of pump=\eta =\frac {Q_2}{W}=\frac {T_f}{T_f-T_i}=313/25=12.5
Now,
Heat \ supplied \ = \eta .W=(12.5)(1200)=15000J=15 KJ
maybe i used g=10..thats why ans is not exact
24well for expalination...u should turn to Page 308 NCERT phy (XI) part 2
1can you explain your 2nd step a bit more
\eta =\frac {Q_2}{W}=\frac {T_f}{T_f-T_i}% ??
