try

11 Answers

11
Mani Pal Singh ·

71 ka answer C hai

1
°ღ•๓яυΠ·

haan kaise??

11
Mani Pal Singh ·

yaar humein copy mein kuch Ka yad rakne ke liye kaha tha
uun mein se yeh ek hai :P

will try u the method after some time

106
Asish Mahapatra ·

Q71 .. H2O -><- H+ + OH-
[H2O] = 55.5 moles/litre.
Now ionisation constant = K of equation = [H+][OH-]/[H2O] = Kw/55.5 = 10-14/55.5 = 1.8*10-16

1
°ღ•๓яυΠ·

arey haan shit ..........sahi yaar yaar
IONISATION CONSTANT poocha hai

1
°ღ•๓яυΠ·

dusre q's bhi bata diyoooo

1
°ღ•๓яυΠ·

try talo ..................try talo.,,.

1
Ragadeepika ·

72.

The solution clearly forms a buffer.

Using henderson equation -->

pOH = pKb + log \frac{[salt]}{[base]}

[salt] = (0.01 * 100)/ 200
[acid] = (0.01 * 100)/200

pKa + pKb = 14 {for a particular conjugate acid-base pair}

pKb = 14 - 9.26 = 4.74

pOH = 4.74 + log 1 = 4.74
Thus, answer is A.

Please correct me, if I'm wrong.
ALL THE BEST

1
°ღ•๓яυΠ·

nice try dear bt dats nt d answer :(

1
Ragadeepika ·

Can you please tell me my mistake !!!

1
°ღ•๓яυΠ·

i dunno i 2 gt d same answer bt woh answer ni hai

can u try d first q also

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