in an insulated vessel,0.05kg steam at 373K and 0.45kg of ice at 253K are mixed .Find final temp of the given mixture.
L(fusion)=336J/g
L(vap)=2268J/g
S(ice)=2100J/kg
S(Water)=4200/kg
ans given is 273..i am getting 262K
my soln is ::
0.05(2.268)+0.05(4200)(T-273)=0.45(2100)(20)+0.45(0.336)+0.45(4200)(T-273)
point out mistake
1T=262K looks contradictory.......
0.45(2.1)(20)-----→ here uve assumed ice has reached 0C and then melted ,by taking \Delta T=20....
If ur ans is 262K, tht means tht the ice hasnt melted...which contradicts ur assumption........
Also, if final t=262k, even the steam must have turned into ice......
1Heat req to melt d ice =0.45(2.1)(20)+0.45(0.336)=19.0512 if final temp. is 273K, then heat given out by steam=0.05(2.268)+0.05(4.2)(100)=21.1134 this means tht the ice melts completely... 0.05(2.268)+0.05(4.2)(373-T)=0.45(2.1)(20)+0.45(0.336)+0.45(4.2)(T-273)
Ans..273.sumthing
