1but tan inverse cotx is equivalent to tan inverse tan (pi/2 - x)...
so what about dat???????????
we have to calculate the value of 1/x in a calculator, but the key of 1/x function is broken and we can only use the functions sinx , cosx. tanx. sin-1x ,cos-1x ,and tan-1x.how itz possible?
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8 Answers
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1tan(cot-1x) wont do. I can tell if -1≤x≤1. then first assume cos z =x then 1/x can be written as ±√(1+tan2z). where z=cos-1x. If -1≤x<0 then take negative sqare root otherwise take positive square root. for other values of x I dont know. I think for other values it will not be in the required domain. (of course make sure your calculator is in radian mode).
21No need to worry about negative numbers, your minus key is not broken. :)
for x>0, tan(cot-1x) will surely do. but cot-1(x) is not there in calculator.:p But \frac{1}{x}= \tan(\arcsin (\cos(\arctan(x)))= \tan(\arccos(\sin(\arctan(x))))
works. Hope that's correct, saw that long back in a book. :)
1i also hav thought it in dis way nd i thnk u r absolutely correct...