simple

Proof that
(tan5A+tan3A)/(tan5A-tan3A)=4cos4Acos2A

2 Answers

1
Yash Sachdev ·

Cant understand answer please write and show but my question is bit different tan5A-tan3A/tan5A-tan3A=sin2A/sin8A

146
Amartya Kumar Mistry ·

it is very easy just simplyfi a bit the expression will become
sin8A/sin2A from there apply sin2θ=2sinθcosθ and after cancelling the terms you will get the answer

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