# Recently Active Trigonometric Functions Questions

• Proof that (tan5A+tan3A)/(tan5A-tan3A)=4cos4Acos2A ...
replied2016-08-23 22:52:33
• Help me with this. I need it urgently. And I want full solution ...
• If Tan A/2 = (Tan B/2)3 and Tan B = 2 Tan C then find (A + B)\C. ...
• If sin Î± + sin Î² = a and cos Î± + cos Î² = b,then prove that sin(Î± + Î²) = (2ab/a2 + b2) ...
replied2014-07-22 03:14:35
• if Î±,Î² are two different values of Î¸ lying between 0 and 2Î which satisfy the equation 6 cos Î¸ + 8 sin Î¸ = 9,then find the value of sin(Î± + Î²). ...
replied2014-07-22 03:00:29
• If angle Î¸ is divided into two parts such that the tangent of one part is Î» times the tangent of the other, and Î± is their difference,show that sinÎ¸ = (Î»+1/Î»-1)sinÎ± ...
replied2014-07-17 05:45:45
• If cosÎ¸=ncos(Î¸+2Î±)then show that (n+1)tan(Î¸+Î±)=(n-1)cotÎ± ...
replied2014-06-23 03:07:35
• Prove that : CotA + Cot(60+a) - Cot(60 -a) = 3Cot3A ...
• Prove that: TanA + Tan(60+a) - Tan(60 -a) = 3Tan3A ...
• the positive values of a for which the equation [x+a]=sin(Ï€x/2) will have no solution is,where [.] denotes greatest integer function- a) (0,1); b)(1,2);c) (0,2);d) NOT. ...
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replied2014-05-21 03:29:23
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replied2014-05-14 09:20:21
• If cos(Î±-Î²)+cos(Î²-Î³)+cos(Î³-Î±)= -3/2 , then p.t. â†’ cosÎ± +cosÎ² +cosÎ³ =sinÎ± +sinÎ² +sinÎ³ =0 . ...
replied2014-04-18 06:49:21
• If tan(inverse)(x+2/x)-tan(inverse)4/x-tan(inverse)(x-2/x)=0 then x=............ y=........... (M.L.Khanna Page 464 Problem No.37a) ...
replied2014-04-17 10:45:20
• Write the following function in the simplest form :- tan_1âˆš 1-x/1+x ...
replied2014-04-10 23:21:39
• Prove that sin2Î¸=(x+y)2/4xy possible for real values of x and y only when x is equal to y. x not equal to 0. ...
replied2014-03-11 03:36:56
• Prove that tan 8Î¸ -tan 6Î¸- tan 2Î¸ = tan 8Î¸ tan 6Î¸tan 2Î¸ ...
replied2014-03-10 22:39:34
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replied2014-03-08 22:35:39
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replied2014-03-08 22:35:23
• If tan2Î¸ = 1-k2,s.t. sec2Î¸+tan3Î¸ cosecÎ¸ = (2-k2)3/2 ...
replied2014-03-07 23:51:54
• A+B+C= Î /2 p.t. +cos2A+cos2B+cos2C=2(1+sinAsinBsinC) ...
replied2014-03-05 23:22:46
• cosec Î¸ = cot Î¸ + âˆš3 ...
replied2014-02-10 15:26:31