inverse trig

(c)

sin inv x/a*√b²-y²/b + y/b*√a²-x²/a = α

x/a*√b²-y²/b + y/b*√a²-x²/a =sinα

square ans see wat ur gettin[1]

quickest way...

to do it within 30 seconds

put

x=a and y=b

then α=180°

[4]

from where iitim... has left...

squaring ...

x²/a² + y²/b² + 2xy/ab[x/a. y/b - √1- x^2/a^2.√1- y^2/b^2] = sin²Î±

=> option C.

since 2xy/ab[x/a. y/b - √1- x^2/a^2.√1- y^2/b^2] = cosα

its ans is c take different option and satisfy it no need to solve yaar

ya itz C ..........im too on rahul's side.........itz time saving........[1][1][1][1][1][1]..............

thanx dude