sin-1x+sin-1y=2Ï€/3.....then the value of x and y are ????
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13Break 2π/3 into ( π/2 + π/6 ).. As we know that sin-1x + cos -1x = π/2, so by replacing π/2 by sin-1x + cos-1x we get :-
=>sin-1x + sin-1 y = sin-1x +cos-1x + π/6
=>sin-1y - cos-1x = π/6
=>sin-1y - sin-1√1-x2 = Ï€/6.... this is the second equation....
the question is the first equation ....solve both,then you will get the answer!!!!!!
