If θ and α are two real numbers such that
( cos4 θ/cos2 α) + (sin4 θ/sin2α) = 1
then prove that: -
(cos2n+2 θ/cos2nα) + (sin2n+2θ/sin2nα) = 1
for integral values of n.
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1 Answers
62( cos4 θ/cos2 α) + (sin4 θ/sin2α) = 1
so,
( cos4 θ. sin2 α) + (sin4 θ. cos2α) = cos2α. sin2α
now u can reduce it to get
(cos2θ-cos2α)2=0!!
This is done by taking sin2α in the numerator in the first step as 1-cos2α
Then again at one stage take sin2θ as 1-cos2θ
U should be through..
Try or else i will give the whole solution :)
