solve this one!!!!!

I think u must have been given some range for ω

(ksin ω + 2 cos ω)/(sin ω+ cos ω)

=2+(k-2)/(1+cotω)

for this to be increasing.. for ω on real line,
only way is k=2 (that too will only make it constant!)

k>2
or k<2

must have been the correct choice.. depending on 1+cot ω is +ve or -ve.

but the data above is insufficient to tell that!

=2 + {(k-2)/(1+cotω)}

so the first 2 is not in the numerator!

(ksin ω + 2 cos ω)/(sin ω+ cos ω)

=((2+k-2)sin ω + 2 cos ω)/(sin ω+ cos ω)

={(k-2)sin ω + 2(sinω + cos ω)}/(sin ω+ cos ω)

={(k-2)sinω/(sinω+cosω)} + 2

hence the above result!

yes i agree sky..