1twas sumthing b/w 0 and 1 obviously
hmm... let me try to remember
in [0,1] , x^{2}(1-x)^{6} attains maximum value at which point?
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6 Answers
1
62x^2(1-x)^6 \\dy/dx = 2x(1-x)^6-6x^2(1-x)^5 \\dy/dx = 0 \\2x(1-x)^6=6x^2(1-x)^5 \\(1-x)=3x\ or \ x=0 \ or \ x=1
Thus you get x=1/4
at x=0 and x=1 f(x) =0
so z=1/4