11dude mere se solve nahin hua tabhie poccha hai
i will be happy to see the solution[1]
6. The A.M. between m and n and G. M. between a and b are each equal to ma+nb /m+n . Then m =
(A) a√b/√a+√b (B) b√a/√a+√b
(C) 2a√b/√a+√b (D) 2b√a/√a+√b
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8 Answers
11
1(m+n)/2 = √(ab) ........(1)
this is equal to (ma+nb)/(m+n)
equate √(ab) = (ma+nb)/{2√(ab)}
then solve for m or n , then substitue in (1)
you'll get it . and then split a-b as (√a + √b )(√a- √b)
11oh noooooooooo
i didn't obserned that AM and GM are equal
GOOD WORK SRI
thanx 4 the help
please help in probability and helllllllllppppp
106AM = (m+n)/2 = GM = √ab
==> (m+n)/2 = √ab = (ma+nb)/(m+n)
equating the first and third
(m+n)2 = 2(ma+nb)
and equating first and second and squaring
(m+n)2 = 4ab
So, 2ab = ma + nb .... (i)
now, equating 2nd and 3rd/
√abm + √abn = am + bn
==> √am(√b - √a) - √bn(√b-√a) = 0
==> m√a = n√b ... (iii)
using (iii) n = m√a/b in (i)
2ab = ma + mb√a/b
==> m = 2ab/(a+√ab)
==> m = 2b√a/(√a+√b)
