71How?
\hspace{-16}$If\; $\mathbf{\frac{\alpha+\beta}{2\alpha+\gamma}=\frac{\beta+\gamma}{2\beta+\alpha}=\frac{\gamma+\alpha}{2\gamma+\beta}}$\\\\\\ Then $\mathbf{\frac{2\alpha+3\beta+5\gamma}{7\alpha+11\beta+13\gamma}=}$
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9 Answers
262we can easily say alpha=beta=gamma ≠0
hence the answer will be 10/31
262if you want to prove it then you can use -
xa + yb + zc = x+y+za+b+c
or as sambit said, the equations are symmetric
36@Aditya - x/a + y/b + z/c ≠(x + y + z)/(a + b + c)
instead, x/a = y/b = z/c = (x + y + z)/(a + b + c)
1in this style of questions, put the equality
the answer is 10/31