1hey im getting (1-n)3=4 by this it has one real & two imaginary i m correct... reply karo...
1
rahul wadhwani
·2009-02-13 00:22:55
eureka reply karo im correct or not
24sorry to say it..but u r incorrect[2].......All 3 roots of n are real....-1,1,3
62small mistake by rahul
determinant of A-nI is
(1-n)3-4(n-1)=0
thus
n=1
or (1-n)2=4
thus (1-n)=+2 or (1-n)=-2
thus n=-1 or n=3
1"roots of n ??"
i thought roots were of an equation...
24
eureka123
·2009-02-13 10:15:42
Is someone trying remaining parts??[12]
21chk for k=2;
i'm getting 11 which is not 2^2 + 1 [11]
24
eureka123
·2009-02-13 11:08:22
First xplain me what is meaning of trace???????
21
tapanmast Vora
·2009-02-13 11:12:26
its da sum of all elements of the aii ie a11 + a22 + a33 = 1 + 1 + 1 for matrix A
24
eureka123
·2009-02-13 11:14:03
then 2 part is easy.........becoz for k=1 it satisfies.....[3]
1
rahul wadhwani
·2009-02-18 01:18:36
thanx nishant bhaiaya sorry for my silly mistake
24
eureka123
·2009-02-18 02:43:51
plz try 4th part.............[2]
