24ok.................[1]
25 Answers
1chem sumwher a multiple will cum which is also a multiple of 49...........
thts y check for 7 first.......if no,forget it...........if yes,then do for 49 at tht time
62@eureka..
skip this for jee
come back after that :)
this is olympiad stuff
24@ rajat..........can u explain what u wrote...........i cant understand...[2][2]
1dog/s tail.......
49,,,........9.....8......7.......6......not 9.....1......9......1
1sorry mistake......
for 49..........it shud be divisble by 7 also.................
ok 1st case
144255...........4 6 4 ..repeats every 2 times....so units digit is 4...
192255........2 4 8 6 2 every 4 times........so last digit is 8....
when u add.........last digit of sum is 12....
for 7.......7 4 1 8 5 2 9 6 blah blah...
for 49...9 8 7 6 ........but no 2.......
so not divisible
1sorryyyyyyyyyyyyyyyyyyyyyyyyyyy.............
im mad today...............
1u have wrote 7,9,3,1,...can u tell me wat r they????????????
units place of wat????????????
1omg!
they r units plce of powes not multiples....forgive me!i m done!
why r u confusing between powers and mutiples...its not that difficult
1dude.........they are not powers...........they are units place of d multiples
1if 2 doesnt in powers doesnt signify its not divisible.....
1for 49..........it shud be divisble by 7 also.................
ok 1st case
144255...........4 6 4 ..repeats every 2 times....so units digit is 4...
192255........2 4 8 6 2 every 5 times........so last digit is 2....
when u add.........last digit of sum is 6....
for 7.......7 9 3 1 7...
6 doesnt cum so it is not divisble................
1dude chem............for 49........last digits are not enuf.......u need more........thts y i have taken for 7
1so last digits 9 , 8 , 7 ,6 ,5 ,4 , .....so it could be divisible...just need to check how to prove....
1chem..........i was seeing for d last digits of multiples of 7...........not 49.............
1for 7.......7 9 3 1 7...
why r u going multiplying with 7......u just need to do this....
49*1
49*2
49*3
.....and so on
1dude mathi.............if it is divisible by 49 then it surely means it is divisible by 7.........I meant tht
1sorry mistake......
for 49..........it shud be divisble by 7 also.................
ok 1st case
144255...........4 6 4 ..repeats every 2 times....so units digit is 4...
192255........2 4 8 6 2 every 4 times........so last digit is 8....
when u add.........last digit of sum is 12....
for 7.......7 9 3 1 7...
2 doesnt cum so it is not divisble................