do this fast....(

Find the remainder when [(2 × 4 × 6 × 8 × 10 ×…× 200) – (1 × 3 × 5 × 7 × 9 ×…× 199)] is divided by 201.

do not take more than 2 min.....

5 Answers

262
Aditya Bhutra ·

has to be 0

11
Sambit Senapati ·

WE can take 3x67 common from both terms, which is equal to 201. So, the remainder is 0

1
johncenaiit ·

If p be the first of n arithmetic means between two numbers,
and q the first of n harmonic means between the same two numbers,
prove that the value of q cannot lie between p and {((n+1)/(n-1))^2}p

1
rishabh ·

@johncena ur 2nd Q isnt clear. hw can there be n arithmetic means bet. 2 nubers??
is it "p is the arithmetic mean of first n natural no.s"

1
johncenaiit ·

if a1,a2,a3,......,an are n arithmetic means between a and b, then

a,a1,a2,a3,..........,b are in AP.

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