floor equations...

\hspace{-16}$Find value of $\bf{x}$ in $\bf{\lfloor 2^x \rfloor+\lfloor 3^x \rfloor=\lfloor 6^x \rfloor}$\\\\ Where $\bf{\lfloor . \rfloor}$ = floor function.

2 Answers

1057
Ketan Chandak ·

any negative number i guess...

262
Aditya Bhutra ·

maybe (-∞,0) U [log62 ,log64)

Your Answer

Close [X]