1@ subhomoy ATGS, your second step is wrong it should be ab-1 / b*sqrt(ab) , and x = 1/ √ab therefore x^2 = 1/ab or a = 1 / bx^2 implies the ax = 1/bx, so y=0
13 Answers
1a and b are variable and therefore,x is variable tooo...we want a graph of y versus x!
49y = a√ab-1b√ab=ab-1√ab = √ab - 1√ab = 1x - x
y=1x - x
49a bit of analysis:
dydx = -1x2-1 (always negative) function wherever defined is decreasing..
d2ydx2 = 2x3
so, d2ydx2 > 0 for x > 0
and, d2ydx2 < 0 for x < 0
so, for x > 0 , the curve is concave when viewed from upward side and for x < 0 , the curve is concave when viewed from downward side..
149ohho...mera silly mistake ka aadat toh abhi serious mistake ka roop le raha hai...! :-/ :'(
21@ subhomoy : Dekha, Shikayat (Complain) na pine ka Parinaam!!
@everyone: To aap shikayat(Complain) peena kab shuru kar rahe hain?
49Complan peene se sab kuch barta hai! ;)
Sirf dimag hi nahi barhta! :P
