H.P help

I think here we shall use the concept of limits.. \lim_{n\rightarrow \infty } \frac{1}{1+n}

But I don't know how it will be answering your question

@ Rahul : there is no closed formula for H.P

take lcm ,do the addition, you will get oddeven ,so cant ve an integer , :)

It was from yahoo answers........... and he got 10 votes for that.........

If i ever meet him, i'll truly shoot him..... '} - - - ///

well the solution is quite simple

lets recall how to sum fractions :D

\frac{1}{2}+ \frac{1}{3} + .... + \frac{1}{2^k}+ \frac{1}{2^k +1}+....

where 2^k is the highest power of two among number in denominators

SUMMATION : lets take lcm. the lcm will contain (2^k)* p₁p₂...

where p₁p₂... are all primes

Now ,
\frac{1}{2}+ \frac{1}{3} + .... + \frac{1}{2^k}+ \frac{1}{2^k +1}+..

= \frac{even + even + ... + odd + even + ..}{2^k p_{1}p_{2}....}
[while summing 2^k there remains product of primes only , which is necessarily odd]
= \frac{odd}{even}

so not an integer