help karo

bhai log.........yahaan madad ki jiye........ye sabhi maine pehle kiye the par ab ho nahin rahe...........

The eqn zn-1 has n roots which are called nth roots of unity.These n roots are 1,α,α2,..........αn-1

Q1 find value of\sum_{r=1}^{n-1}{\frac{1}{2-\alpha ^{r}}}

12 Answers

1
°ღ•๓яυΠ·

wow i was waitin 4 ur q's ......tryi n :D

24
eureka123 ·

thodi si correction hai,,,,,,,info missing thi....ab bataoo.....

1
°ღ•๓яυΠ·

oye ni samajh ra:(
koi idae hai kya

bus itna samjah ki we can use sum n product of roots as 0 and -1 sumwer

bt woh series ni pallel padh ra

24
eureka123 ·

Q2 Q2 If ω is non real complex cube root of unity then find value of.......\frac{\prod_{p=1}^{4}{(\omega +\alpha ^{p})}}{\prod_{q=1}^{7}{(\omega ^{2}-\alpha ^{q})}}

24
eureka123 ·

who said????

24
eureka123 ·

Q3 If n\varepsilon N,
then \prod_{r=1}^{n-1}{sin(\frac{r\pi }{n})=??}

24
eureka123 ·

Q4 \prod_{k=1}^{n-1}{\frac{1}{1-\alpha _{k}}}

21
tapanmast Vora ·

OPTIONS??????

24
eureka123 ·

options bhi chahiye???????

62
Lokesh Verma ·

Q1 hint

f(x) has roots a1,a2... an

then

f(2-x) has roots 2-a1, 2-a2,.... 2-an

Now it is one step far from the final answer! ? or is it not?

24
eureka123 ·

Sir ,,, can u solve one part fully?? so that i can try the rest of them then.............plzzzzzzzzzzzzzz[2][2]

62
Lokesh Verma ·

f(x) has roots a1,a2... an

then

f(2-x) has roots b1=2-a1, b2=2-a2,.... bn=2-an

Now it is one step far from the final answer! ? or is it not?

you have to find the

1/b1+1/b2+.........1/bn

which is same as sum of product of n-1 taken together ... whole divided by the product of all..

now use the simple rules to find these ....

(2-x)n-1 = constant term will be 2n-1
coeff of x is -n.2n-1
coeff of xn=(-1)n

now is it simple?

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