i power i

sorry hadbadi me gadbadi.. ...

try i = e^iz

find z and then try...

one prooof:
x = ln(iⁱ)
x = i ln(i)
i √-1
x = (i/2) ln(-1)

ln(-1) = i(pi)?? (how?)
x = (i . i . (pi)) /2
x = -(pi)/2
iⁱ= e^-pi/2 = .28 (if i remember correctly!)

now tell what is the mistake!

U will get some reference on the net saying that this iis the actual value..
But this is not!!!

actually ... 0.207879576

But there is a small flaw here!

Find it!

or may be you could say a small thing that was overlooked!

e^(i*pi) = -1

yahan thoda sa locha hai...

like it could even be

e^(i*3pi) = -1

so then, the answer would be

e^(-3pi/2), which is not 0.2079 .

infact iⁱ is e^(2n+1)pi for all integers N

So it is indeterminate!! it is something like 0/0 can take so many values!