limits

i want to check my ans for the question

limx→∞((x-1)(x-2)(x-3)(x+5)(x+10))1/5-x is

27 Answers

62
Lokesh Verma ·

more hint

what is

limit x going to infinity ( x5-1 )1/5-x

limit x going to infinity ( x5-a x4 )1/5-x

62
Lokesh Verma ·

lets take this

(x5+ax4+....+c)1/5-x

=x {(1+a/x+....+c/x5)1/5-1}

we know that

(1+t)1/5 = 1+1/5t+.... higher powers ...

hence the above will be similar to

x{(1+a/5x+... higher orders of 1/x!)-1}

hence this will be a/5....

when x goes to infinity...

here in the above question, a=-9

hence.. -9/5

33
Abhishek Priyam ·

[3][3][3][3]
waise maine bhi to 9/5 hi kaha tha .... [3] (-1/5)+2

[6]

edited there [2]

33
Abhishek Priyam ·

Curses be on me...

[2]
[2]
[2]
[2]
[2]

are wahi hai [6]

galti ho jata hai...

mere par mat haso.. [2]

sabse pahle maine hi ye kaha tha ....

http://targetiit.com/iit_jee_forum/posts/limits_387.html

11
Anirudh Narayanan ·

Guys, I don't understand a thing of what is going on here from the beginning [2]

Pls post your complete thought process along with your replies, guys. Please.

1
Philip Calvert ·

ya i was thinking the same
what do you have to say pirate [3]

62
Lokesh Verma ·

If i were to make a tukka for this one!

my tukka says

(-1-2-3+5+10)/5 = 9/5

33
Abhishek Priyam ·

[2]

don't laugh on my mistake in tukka atleast

Nishant Bhaiya:(It is not very very simple.. but doable!)

but i did it in 10 secs without any pen... with my tukka....
yipieeeeeee [4]

62
Lokesh Verma ·

did the tukka master make an addition mistake?

33
Abhishek Priyam ·

[2]

no forgot to divide by 5 ... the key in tukka

33
Abhishek Priyam ·

same question here also :

and my same tukka there also [3]

http://targetiit.com/iit_jee_forum/posts/limits_387.html

1
Philip Calvert ·

hmmm.....
strange tukkas and strange typing errors [4]

33
Abhishek Priyam ·

typing mistake..

thats (-1+10)/5 [3]

i.e. (-1/5)+2 [3]

it for sure (-1/5)+2.. [3]

with my evergreen tukka...
:P

33
Abhishek Priyam ·

{ (x-1)(x-1)(x-1)(x-1)(x-1) }1/5 - x

it is -1 ?

so taht should be 10

3
msp ·

i have got the ans as 0

33
Abhishek Priyam ·

is the answer 10

just a classic tukka [3]

[7]

[7]

[7]

3
msp ·

sir thnx .i didnt think abt this.

62
Lokesh Verma ·

take another example

{ (x-1)(x-1)(x-1)(x-1)(x-1) }1/5 - x

what will it be ??

If this is not zero.. then can u justify it for another arbitrary polynomial?

3
msp ·

why sir.why my app is wrong.

62
Lokesh Verma ·

do u realise how to solve the previous question that i posted!?

then u may be able to get the thought process going!

(It is not very very simple.. but doable!)

62
Lokesh Verma ·

no we cant sankara..

same with the problem that i gave!

3
msp ·

(x-1)(x-2)(x-3)(x+5)(x+10) this term is equal to x5 when x approaches to infinity so that the exp reduces to limx→∞(x-x) which is zero. please correct me.

39
Dr.House ·

how to do with 1/5 in the power???

39
Dr.House ·

areh sir that one is easy

bring that into denominator by multiplying with came term with + in between

3
msp ·

sir can we consider (x-1)(x-2) the terms as x2 when x tends to infinity.

62
Lokesh Verma ·

Hint

try solving this one

limx→∞((x-1)(x-2))1/2-x is

39
Dr.House ·

sorry me also clueless

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