the question should be a/(b+c) +b/(c+a) + c/(a+b)
6 Answers
kaymant
·2009-08-11 22:57:54
in which case the answer would be 3/2. the famed Nesbitt's.
P.S. yes.. 3/2 is the minimum. Thanx rahul for pointing it out. But then the given expression does not have an absolute maximum as can be seen by taking any two of a,b,c → 0.
Aditya Balasubramanyam
·2009-08-12 04:12:29
I did'nt Undertsand ... .. Can u please tell me how did you solve it?
rahul1993 Duggal
·2009-08-12 04:14:30
@aditya
you can check out various proofs of nesbitt's inequality here http://en.wikipedia.org/wiki/Nesbitt's_inequality
Dr.House
·2009-08-12 04:37:57
http://targetiit.com/iit-jee-forum/posts/iit-jee-past-question-trigonometry-4026.html
http://targetiit.com/iit-jee-forum/posts/07-03-09-prove-this-inequality-3323.html
should also help u