11only one value will exist which is
x=22345
x=2abcd .How many different values of x exist if a=2,b=3,c=4,d=5
(I have made up this question so it may get a bit long.....)
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10 Answers
24wrong dude...we can combine these terms in diff ways(un conventionally)
heres eg
2(ab)cd
or 2a(bc)d
many other will exist.......try it..
11how come 23=2X3 ????
how can we combine them
[5][5][5][5][5][5][5][5][5]`
24we can do that in the powers....
and i wrote the word unconventionally.......
11u mean to say that
232=26=64
but what i know is
232=29=512
sorry if i am wasting ur time
but this is all i know
i think i may better not try this 1
24ya thats what i want to say.......by rearranging the powers we get diff answers........
thats why my heading is P&C.......
it is similar to arranging 4 students on 4 seats...where they have likes and dislikes to be paired in group of 2 ,3 or 4 even....
11but according to u which one is correct
232=26=64
or
232=29=512??????
24oh my god............
i simply dont understand why u dont understand..[3][3]
the question is asking u to find number of ways of grouping a,b,c,d
1what is wrong with this 1
Eureka post what r u trying to say
the answer to #1 is
22345