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Q6 4 boys and 3 girls ........... find the no. of ways to seat them on a circular table such that no two girls sit together. a) 0 b) 3!*4! c) 3!*3! d) 3! Correct Answer: (b)

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Asish Mahapatra ·2009-02-18 04:05:48

seat whom on a circular table??

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big looser ......... ·2009-02-18 04:11:31

now check it

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Asish Mahapatra ·2009-02-18 04:12:19

see there are 4 boys and 3 girls....
first put 4 boys on table.
no. of ways to seat 4 boys on circular table = (4-1)! = 3!
Now from 4 spaces left, 3 girls have to be seated. So, no. of arrangements = 4P₃ = 4!/(4-3)! = 4!
So, total no. of arrangements = 3!*4!

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big looser ......... ·2009-02-18 04:13:30

thanks bro.. i was counting 5 spaces

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Basic Integral Calculus Operators Symbols Matrix Cases

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∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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