probability with infinity no of outcomes

for the 22nd qn If two nos x and y are chosen from the set of all natural numbers the probability that x2+y2 is divisible by 5 must be

4 Answers

3
msp ·

pls solve and post ur soln.

11
rkrish ·

Q21)

Sn : {n | n2+1} : Given sequence

In every 5 succesive terms of Sn , 2 terms are divisible by 5

So ,
P = Lt n → ∞ 2 \frac{[\frac{n}{5}]}{n} = \frac{2}{5}

11
rkrish ·

Q22)

Last digit Last digit
of x2 of y

1 4,9
4 1,6
9 6,1
6 9,4
5 0,5

For any x you choose probability of choosing a y such that x2 + y is divisible by 5 is 2/10 = 1/5 [ last digit of y should be any one of the two mentioned above out of 0 - 9 ]

Hence , P = \frac{1}{5}

3
msp ·

hey krish i have editd the last qn sry for the fault.

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