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Prove that 3b2+6ac≤(a+b+c)2 if a≥b≥c

3 Answers

24
eureka123 ·

this is inequalities question dear.....

1
? ·

the equality condition can be proved directly applying the formula

(a+b+c)2 = a2+b2+c2 + 2ab + 2bc + 2ca

when a=b=c,

its (a+b+c)2 = b2+b2+b2+6ac

1
? ·

its lesser than or equal to !!

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