11k + p = kevin + pietersen = kevin pietersen [3][3][3][3][3][3][3][3][
k is an integer, p is a prime no.
such that x2+kx+p=0 has distinct +ve integral roots.
Find the value of (k+p).
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8 Answers
1111ya rite,ans. is -1...& k has to be -ve....but how do you find out (k+p) without substituting values for k & p [7][7]
21used the logic nishant bhaiyya taught me earlier....
k negative coz both roots +ve (descarte's thrm appln)
Diff of 2 odd sq = 8n
{ chk out dis link : http://targetiit.com/iit_jee_forum/posts/quadratic_2024.html }
D2 - k2 = -4p;
only val of p such dat 4p = 8n is 2 so u get ur p
(-3)2 - 4*2 = 12
-3 + 2 = -1......
341If the roots are +ve integers and their product is p, then they have to be 1 and p.
So k = -(1+p) which means k+p = -1
21YEAH PROPHET SIR!!!!
MUCH BETTER SOLN. THEN MINE COZ THER ARE A FEW ASSUMPTNS IN MY METH.....